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Proof step 18 from proof int2bits-len-mon (previous step)

j < 0, j < i, i + j < 0, # int2bits(~ j - 1) < # uint2bits(i), 0 ≤ i, j < 0 ⊦ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
0 ≤ i, j < 0, j < i, i + j < 0, # int2bits(~(j + 1)) < # uint2bits(i) ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ~ i - j = ~(i + j);