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Proof step 25 from proof int2bits-len-mon (previous step)

1 < abs(j), i < 0, # int2bits(j) < # int2bits(i), 0 < abs(j) + i ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 26:
⊦ i < 0 → # int2bits(i) = # int2bits(~ i - 1)
Proof step 27:
i < 0, 1 < abs(j), i < 0, # int2bits(j) < # int2bits(~ i - 1), 0 < abs(j) + i ⊦ j = 0

Rule argument

name: int2bits-len-neg-01 rotate: F subst: [i] → [i]

Additional information

Used terms: i