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Proof step 28 from proof int2bits-len-mon (previous step)

# int2bits(j) < # int2bits(~(i + 1)), i < 0, 1 < abs(j), 0 < abs(j) + i ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 29:
⊦ j < 0 → abs(j) = 0 - j
Proof step 30:
¬ j < 0, # int2bits(j) < # int2bits(~(i + 1)), i < 0, 1 < abs(j), 0 < abs(j) + i ⊦ j = 0
Proof step 38:
j < 0, # int2bits(j) < # int2bits(~(i + 1)), i < 0, 1 < 0 - j, 0 < (0 - j) + i ⊦ j = 0

Rule argument

seq: ⊦ j < 0 → abs(j) = 0 - j subst: [j] → [j] rotate: F spec: int-abs inst: name: Abs-neg

Additional information

Used terms: j