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Proof step 41 from proof int2bits-len-mon (previous step)

j < 0, j < 0, j < i, i < 0, # int2bits(~ j - 1) < # int2bits(~(i + 1)), j < ~1 ⊦ j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 42:
j < ~1, j < 0, j < i, i < 0, # int2bits(~(j + 1)) < # int2bits(~(i + 1)) ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ ~ i - j = ~(i + j);