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Proof step 10 from proof int2bits-len-neg-02 (previous step)

j + 2 ^ i = 0, j < 0 ⊦ # int2bits(~(j + 1)) = # int2bits(~ j), ∃ i. 2 ^ i + j = 0

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: i

Additional information

Used simplifier rules: ⊦ i + j = j + i; Used terms: i