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Proof step 2 from proof int2bits-len-one (previous step)

# int2bits(i) = 1, 0 < i ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 4:
0 ≤ i, # uint2bits(i) = 1, 0 < i ⊦ i = 0

Rule argument

name: int2bits-pos rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: i