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Proof step 5 from proof int2bits-len-one (previous step)

# uint2bits(i) = 1, 0 < i ⊦ i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: uint2bits-rec rotate: F subst: [i] → [i]

Additional information

Used simplifier rules: uint2bits-one: ⊦ uint2bits(1) = false + true;%uint2bits-empty: 0 ≤ i ⊦ uint2bits(i) ≠ [];% ⊦ boolvar + boolvar0 = boolvar ' + boolvar0 ';% ⊦ 0 < i → (i ≤ 1 ↔ i = 1);% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ bits + boolvar = bits + boolvar ';% ⊦ #(bits + bits0) = # bits + # bits0;% ⊦ # boolvar ' = 0 +1;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ 1 = m + 1 ↔ m = 0;% ⊦ # bits = 0 ↔ bits = [];% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ 0 ≤ i / 2 ↔ ~1 ≤ i;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: i