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Proof step 5 from proof int2bits-len-pos-02 (previous step)

0 < j, 0 ≤ i, 0 ≤ 2 ^ i ⊦ # uint2bits(j * 2 ^ i) = # int2bits(j) + i→n(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 < j ∧ 0 ≤ i → # uint2bits(j * 2 ^ i) = # uint2bits(j) + i→n(i)
Proof step 7:
0 < j ∧ 0 ≤ i, 0 < j, 0 ≤ i, 0 ≤ 2 ^ i ⊦ # uint2bits(j) + i→n(i) = # int2bits(j) + i→n(i)

Rule argument

name: uint2bits-len-pos rotate: F subst: [i, j] → [i, j]

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false); Used terms: i, j