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Proof step 2 from proof int2bits-len-pos-pred (previous step)

0 ≤ j ⊦ # int2bits(j - 1) = # int2bits(j), ∃ i. 2 ^ i = j

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1))
Proof step 4:
0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)), 0 ≤ j ⊦ # int2bits(j - 1) = # int2bits(j), ∃ i. 2 ^ i = j

Rule argument

seq: ⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)) subst: [j] → [j] rotate: F spec: int-pot inst: name: exin2pot

Additional information

Used terms: j