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Proof step 2 from proof int2bits-len-pos (previous step)

j < 2 ^ i * 2, 2 ^ i ≤ j, 0 ≤ i, 0 < j, 0 < 2 ^ i ⊦ # int2bits(j) = i→n(i + 2)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 4:
0 ≤ j, j < 2 ^ i * 2, 2 ^ i ≤ j, 0 ≤ i, 0 < j, 0 < 2 ^ i ⊦ # uint2bits(j) = i→n(i + 2)

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i; Used terms: j