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Proof step 1 from proof int2bits-len-range (conclusion)

~(2 ^ i) ≤ j, j < 2 ^ i ⊦ # int2bits(j) ≤ i→n(i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i→n(i + 1) < # int2bits(j), 0 ≤ 2 ^ i + j, j < 2 ^ i ⊦

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ m ≤ n ↔ n < m;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;