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Proof step 13 from proof int2bits-leneq-pos (previous step)

0 < j ⊦ j < 2 ^ (n→i(# int2bits(j)) - 1), j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
0 < j, 2 ^ (n→i(# int2bits(j)) - 1) ≤ j ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs