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Proof step 17 from proof int2bits-leneq-pos (previous step)

i→n(n→i(# int2bits(j)) - 1) + 1 < # int2bits(j), 0 < j ⊦ j = 0

User applied rule insert elim lemma

And obtained the following new goals

Proof step 18:
n→i(# int2bits(j)) = i0 + 1, i→n(i0) + 1 < # int2bits(j), 0 < j ⊦ j = 0

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [n→i(# int2bits(j)), 1, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: n→i(# int2bits(j)), 1, i