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Proof step 2 from proof int2bits-less-2pot-02 (previous step)

0 ≤ j, 2 ^ n→i(# int2bits(j)) < j ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
0 ≤ j ⊦ j < 2 ^ (n→i(# int2bits(j)) - 1)
Proof step 4:
j < 2 ^ (n→i(# int2bits(j)) - 1), 0 ≤ j, 2 ^ n→i(# int2bits(j)) < j ⊦

Rule argument

name: int2bits-less-2pot subst: [j] → [j]

Additional information

Used terms: j