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Proof step 9 from proof int2bits-less-2pot (previous step)

# int2bits(j) < # uint2bits(j), 2 ^ (n→i(# int2bits(j)) - 1) ≤ j, 0 ≤ j ⊦ int2bits(j) = false '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used simplifier rules: uint2bits-zero-01: 0 ≤ i ⊦ uint2bits(i) = false ' ↔ i = 0;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ n < n; Used terms: j