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Proof step 1 from proof int2bits-lslen-05 (conclusion)

⊦ i < ~1 → (m < # int2bits(i) ↔ ¬ 0 ≤ i + 2 ^ (n→i(m) - 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < ~1, i < 0 ⊦ m < # int2bits(i) ↔ ¬ 0 ≤ i + 2 ^ (n→i(m) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ m < n ↔ n ≤ m;% ⊦ i < (* j) ∧ j < 0 → i < 0; (forward)