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Proof step 1 from proof int2bits-lslen-06 (conclusion)

⊦ 0 < i → (m < # int2bits(i) ↔ ¬ i < 2 ^ (n→i(m) - 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 < i ⊦ m < # int2bits(i) ↔ ¬ i < 2 ^ (n→i(m) - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ m < n ↔ n ≤ m;