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Proof step 18 from proof int2bits-lslen-07 (previous step)

# int2bits(j) + 1 < # int2bits(j + 1) ⊦ j < 0

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 19:
⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1))
Proof step 20:
0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)), # int2bits(j) + 1 < # int2bits(j + 1) ⊦ j < 0

Rule argument

seq: ⊦ 0 < j → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j ∧ j < 2 ^ (i + 1)) subst: [j] → [j] rotate: F spec: int-pot inst: name: exin2pot

Additional information

Used terms: j