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Proof step 28 from proof int2bits-lslen-07 (previous step)

0 ≤ i, 0 < j, 2 ^ i ≤ j, i→n(i + 2) + 1 < # int2bits(j + 1), j < 2 ^ i * 2 ⊦ ¬ j + 1 < 2 ^ i, 0 = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
j < 2 ^ i * 2, i→n(i + 2) + 1 < # int2bits(j + 1), 2 ^ i ≤ j, 0 < j, 0 ≤ i, j + 1 < 2 ^ i ⊦ 0 = j

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;