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Proof step 32 from proof int2bits-lslen-07 (previous step)

j + 1 < 2 ^ i, j + 1 < 2 ^ (i - 1), j < 2 ^ i * 2, i→n(i + 2) + 1 < # int2bits(j + 1), 2 ^ i ≤ j, 0 < j, 0 < i ⊦ 0 = j, 0 = i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 33:
⊦ i + j = j + i
Proof step 34:
1 + j < 2 ^ i, 1 + j < 2 ^ (i - 1), j < 2 ^ i * 2, i→n(i + 2) + 1 < # int2bits(1 + j), 2 ^ i ≤ j, 0 < j, 0 < i ⊦ 0 = j, 0 = i

Rule argument

seq: ⊦ i + j = j + i subst: [j, i] → [1, j] rotate: F spec: int-basic2 inst: name: add-c

Additional information

Used terms: 1, j