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Proof step 37 from proof int2bits-lslen-07 (previous step)

2 ^ i * 2 = j + 1, i→n(i + 2) + 1 < # int2bits(j + 1), 2 ^ i ≤ j, 0 ≤ i, 0 < j ⊦ 0 = j

User applied rule insert equation

And obtained the following new goals

Proof step 38:
i→n(i + 2) + 1 < # int2bits(2 ^ i * 2), 2 ^ i ≤ j, 0 ≤ i, 0 < j ⊦ 0 = j

Rule argument

pos: left 1 flags: rotate, discard

Additional information