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Proof step 39 from proof int2bits-lslen-07 (previous step)

0 < j, 0 ≤ i, 2 ^ i ≤ j, i→n(i + 2) + 1 < # int2bits(2 ^ i * 2) ⊦ 0 = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 40:
⊦ 0 ≤ i → j ^ (i + 1) = j ^ i * j
Proof step 41:
0 ≤ i, 0 < j, 0 ≤ i, 2 ^ i ≤ j, i→n(i + 2) + 1 < # int2bits(2 ^ (i + 1)) ⊦ 0 = j

Rule argument

seq: ⊦ 0 ≤ i → j ^ (i + 1) = j ^ i * j subst: [i, j] → [i, 2] rotate: T spec: int-pot inst: name: succ

Additional information

Used terms: i, 2