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Proof step 2 from proof int2bits-lslen (previous step)

0 < i ⊦ # int2bits(i) < m ↔ ¬ 2 ^ (n→i(m) - 2) ≤ i

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < i → (# int2bits(i) ≤ m ↔ i < 2 ^ (n→i(m) - 1))
Proof step 4:
0 < i → (# int2bits(i) ≤ m -1 ↔ i < 2 ^ (n→i(m -1) - 1)), 0 < i ⊦ # int2bits(i) < m ↔ ¬ 2 ^ (n→i(m) - 2) ≤ i

Rule argument

name: int2bits-lelen subst: [i, m] → [i, m -1]

Additional information

Used terms: i, m -1