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Proof step 8 from proof int2bits-lslen (
previous step
)
n→i(m0) = i0 + 1, ¬ m0 < # int2bits(i) ↔ i < 2 ^ i0, 0 < i ⊦ # int2bits(i) ≤ m0 ↔ ¬ 2 ^ i0 ≤ i
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 9
:
n→i(m0) = i0 + 1, ¬ m0 < # int2bits(i) ↔ i < 2 ^ i0, 0 < i ⊦ # int2bits(i) ≤ m0 ↔ ¬ 2 ^ i0 ≤ i
Rule argument
Additional information