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Proof step 1 from proof int2bits-mod2-neg (conclusion)

⊦ i ≤ 0 → int2bits(i % 2) = int2bits(i).last '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ 0 ⊦ int2bits(i % 2) = int2bits(i).last '

Rule argument

Additional information

Used simplifier rules: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)