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Proof step 3 from proof int2bits-mod256 (previous step)

256 = 2 ^ 8, 0 < j, 0 ≤ j0, j0 < 256 ⊦ int2bits(j * 256 + j0) = int2bits(j) + fillsgn(9, int2bits(j0)).rest

User applied rule insert equation

And obtained the following new goals

Proof step 4:
0 < j, 0 ≤ j0, j0 < 2 ^ 8 ⊦ int2bits(j * 2 ^ 8 + j0) = int2bits(j) + fillsgn(9, int2bits(j0)).rest

Rule argument

pos: left 1 flags: discard

Additional information