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Proof step 8 from proof int2bits-neg-02 (previous step)

sgn(int2bits(2 ^ n→i(# int2bits(~ j)) - ~ j).rest) = int2bits(2 ^ n→i(# int2bits(~ j)) - ~ j).rest, j < 0, j < 0 ⊦ sgn(int2bits(2 ^ n→i(# int2bits(~ j)) + j).rest) = int2bits(2 ^ n→i(# int2bits(~ j)) + j).rest, ∃ i. 2 ^ i + j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ i - ~ j = i + j;