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Proof step 10 from proof int2bits-neg-03 (previous step)

j < 0 ⊦ int2bits(2 ^ n→i(# int2bits(~ j)) + j).rest ≠ [], int2bits(j) = sgn(int2bits(2 ^ n→i(# int2bits(~ j)) + j).rest)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
int2bits(2 ^ n→i(# int2bits(~ j)) + j).rest = [], j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ [];% ⊦ sgn([]) = [];