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Proof step 12 from proof int2bits-neg-03 (previous step)

int2bits(2 ^ n→i(# int2bits(~ j)) + j) = boolvar + bits ∧ int2bits(2 ^ n→i(# int2bits(~ j)) + j) ≠ [], bits = [], j < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
int2bits(2 ^ n→i(# int2bits(~ j)) + j) = boolvar ', j < 0 ⊦

Rule argument

Additional information

Used simplifier rules: int2bits-not-empty: ⊦ int2bits(j) ≠ [];% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + [] = bits;% ⊦ boolvar + bits = boolvar ' + bits;