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Proof step 33 from proof int2bits-neg-03 (previous step)

¬ ~1 ≠ (2 ^ n→i(# int2bits(~ j)) + j) % 2, sgn((bitsinvert(uint2bits(~((2 ^ n→i(# int2bits(~ j)) + j) / 2))) + (~1 ≠ (2 ^ n→i(# int2bits(~ j)) + j) % 2)')+1) = boolvar ', j < 0, 2 ^ n→i(# int2bits(~ j)) + j < 0 ⊦ ~1 = 2 ^ n→i(# int2bits(~ j)) + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
~1 = (2 ^ n→i(# int2bits(~ j)) + j) % 2, sgn(bitsinvert(uint2bits(~((2 ^ n→i(# int2bits(~ j)) + j) / 2))) + true ') = boolvar ', j < 0, 2 ^ n→i(# int2bits(~ j)) + j < 0 ⊦ ~1 = 2 ^ n→i(# int2bits(~ j)) + j

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ bits + boolvar = bits + boolvar ';% ⊦ (bits + false ')+1 = bits + true;