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Proof step 39 from proof int2bits-neg-03 (previous step)

~1 ≠ (2 ^ n→i(# int2bits(~ j)) + j) % 2, sgn(bitsinvert(uint2bits(~((2 ^ n→i(# int2bits(~ j)) + j) / 2))) +1 + false) = boolvar ', j < 0, 2 ^ n→i(# int2bits(~ j)) + j < 0 ⊦ ~1 = 2 ^ n→i(# int2bits(~ j)) + j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
sgn(bitsinvert(uint2bits(~((2 ^ n→i(# int2bits(~ j)) + j) / 2))) +1 + false ') = boolvar ', j < 0, 2 ^ n→i(# int2bits(~ j)) + j < 0 ⊦ ~1 = 2 ^ n→i(# int2bits(~ j)) + j, ~1 = (2 ^ n→i(# int2bits(~ j)) + j) % 2

Rule argument

Additional information

Used simplifier rules: ⊦ bits + boolvar = bits + boolvar ';