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Proof step 43 from proof int2bits-neg-03 (previous step)

uint2bits(2 ^ n→i(# int2bits(~ j)) + j) = boolvar ', j < 2 ^ n→i(# int2bits(~ j)), 0 < 2 ^ n→i(# int2bits(~ j)), 0 ≤ 2 ^ n→i(# int2bits(~ j)) + j, j < 0, j + 1 < 2 ^ n→i(# int2bits(~ j)) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 44:
⊦ 0 < i → uint2bits(i) ≠ boolvar '
Proof step 45:
¬ 0 < 2 ^ n→i(# int2bits(~ j)) + j, uint2bits(2 ^ n→i(# int2bits(~ j)) + j) = boolvar ', j < 2 ^ n→i(# int2bits(~ j)), 0 < 2 ^ n→i(# int2bits(~ j)), 0 ≤ 2 ^ n→i(# int2bits(~ j)) + j, j < 0, j + 1 < 2 ^ n→i(# int2bits(~ j)) ⊦

Rule argument

name: uint2bits-eq rotate: F subst: [boolvar, i] → [boolvar, 2 ^ n→i(# int2bits(~ j)) + j]

Additional information

Used terms: boolvar, 2 ^ n→i(# int2bits(~ j)) + j