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Proof step 2 from proof int2bits-neg-num (previous step)

i < 0 ⊦ int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < 0 ⊦ int2bits(i) = sgn(bitsinvert(uint2bits(~ i)) +1)

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;