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Proof step 4 from proof int2bits-pred (previous step)

0 ≤ j - 1, 0 < j ⊦ uint2bits(j - 1) = sgn(bitsinvert(bitsinvert(int2bits(j)) +1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j ⊦ uint2bits(j - 1) = sgn(bitsinvert(bitsinvert(int2bits(j)) +1))

Rule argument

Additional information

Used simplifier rules: ⊦ 1 ≤ i ↔ 0 < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;