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Proof step 5 from proof int2bits-rec-neg-01 (previous step)

j < ~1, j < 0 ⊦ j = ~1, (j % 2 ≠ 0)' = int2bits(j % 2)

User applied rule cut formula

And closed the goal!

Rule argument

fma: j % 2 = 0

Additional information

Used simplifier rules: int2bits-eq: ⊦ int2bits(j) = false ' ↔ j = 0;%int2bits-true: ⊦ int2bits(j) = true ' ↔ j = ~1;% ⊦ j < 0 → (j % 2 ≠ ~1 ↔ j % 2 = 0); Used formulas: j % 2 = 0