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Proof step 2 from proof int2bits-rec-neg-02 (previous step)

j % 2 = 0, j < 0 ⊦ int2bits(j) = int2bits(j / 2) + false '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ j < 0 ∧ j ≠ ~1 → int2bits(j) = int2bits((j - 1) / 2) + (~1 = j % 2)'
Proof step 4:
j < 0 ∧ j ≠ ~1, j % 2 = 0, j < 0 ⊦ int2bits((j - 1) / 2) + (~1 = j % 2)' = int2bits(j / 2) + false '

Rule argument

name: int2bits-rec-neg rotate: F subst: [j] → [j]

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: j