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Proof step 2 from proof int2bits-rec-neg (previous step)

j < 0 ⊦ j = ~1, int2bits(j) = int2bits((j - 1) / 2) + (~1 = j % 2)'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i < 0 → int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)
Proof step 4:
j < 0, j < 0 ⊦ j = ~1, sgn(bitsinvert(uint2bits(abs(j))) +1) = int2bits((j - 1) / 2) + (~1 = j % 2)'

Rule argument

name: int2bits-neg rotate: F subst: [i] → [j]

Additional information

Used terms: j