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Proof step 2 from proof int2bits-rec-pos (previous step)

1 < i, 0 < i, 0 ≤ i ⊦ int2bits(i) = int2bits(i / 2) + (i % 2 = 1)'

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 4:
0 ≤ i, 1 < i, 0 < i, 0 ≤ i ⊦ uint2bits(i) = int2bits(i / 2) + (i % 2 = 1)'

Rule argument

name: int2bits-pos rotate: F subst: [i] → [i]

Additional information

Used terms: i