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Proof step 21 from proof int2bits-rest (previous step)

j < 0, j < ~1 ⊦ j = ~1, j = 0, j % 2 = 0, true ∈ uint2bits(~(j / 2))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ j < 0 → true ∈ uint2bits(~ j)

Rule argument

name: uint2bits-onein-01 rotate: F subst: [j] → [j / 2]

Additional information

Used simplifier rules: 0 < j ⊦ i / (* j) < 0 ↔ i + j ≤ 0;% ⊦ i + (* j) ≤ (* j0) ↔ i ≤ j0 - j;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < 0 → (~2 < i ↔ i = ~1);% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: j / 2