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Proof step 14 from proof int2bits-restsgn (previous step)

0 < 2 ^ (i + 2), 0 ≤ 2 ^ (i + 2), j ≤ 2 ^ (i + 2), 0 < 2 ^ i, 0 < j, j < 2 ^ i * 2, 2 ^ i ≤ j, 0 ≤ i ⊦ sgn(uint2bits(2 ^ (i + 2) - j).rest) = uint2bits(2 ^ (i + 2) - j).rest, 0 = j, ∃ i. 2 ^ i = j

User applied rule exists right

And obtained the following new goals

Proof step 15:
0 < 2 ^ (i + 2), 0 ≤ 2 ^ (i + 2), j ≤ 2 ^ (i + 2), 0 < 2 ^ i, 0 < j, j < 2 ^ i * 2, 2 ^ i ≤ j, 0 ≤ i ⊦ sgn(uint2bits(2 ^ (i + 2) - j).rest) = uint2bits(2 ^ (i + 2) - j).rest, 0 = j, 2 ^ (i + 2) = j, ∃ i. 2 ^ i = j

Rule argument

pos: right 3 terms: i + 2 abort: F discard: F computed: F

Additional information

Used terms: i + 2