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Proof step 4 from proof int2bits-sgn-02 (previous step)

¬ 0 ≤ j ⊦ j = 0, j = ~1, sgn(int2bits(j) + bits) = int2bits(j) + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
j < 0 ⊦ j = 0, j = ~1, sgn(int2bits(j) + bits) = int2bits(j) + bits

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;