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Proof step 7 from proof int2bits-sgn-02 (previous step)

j < 0, j < 0 ⊦ j = 0, j = ~1, sgn(sgn(bitsinvert(uint2bits(abs(j))) +1) + bits) = sgn(bitsinvert(uint2bits(abs(j))) +1) + bits

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j < 0 ⊦ j = 0, j = ~1, sgn(bitsinvert(uint2bits(~ j)) +1 + bits) = sgn(bitsinvert(uint2bits(~ j)) +1) + bits

Rule argument

Additional information

Used simplifier rules: ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1;% ⊦ sgn(sgn(bits) + bits0) = sgn(bits + bits0);% ⊦ i < 0 → abs(i) = ~ i;