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Proof step 2 from proof int2bits-succ-intro (previous step)

0 ≤ j ⊦ int2bits(j) = sgn(bitsinvert(bitsinvert(int2bits(j + 1)) +1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 4:
0 ≤ j, 0 ≤ j ⊦ uint2bits(j) = sgn(bitsinvert(bitsinvert(int2bits(j + 1)) +1))

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used terms: j