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Proof step 6 from proof int2bits-succ-intro (previous step)

0 ≤ j, 0 ≤ j, 0 ≤ j ⊦ sgn(bitsinvert(bitsinvert(uint2bits(j + 1)) +1)) = sgn(bitsinvert(bitsinvert(int2bits(j + 1)) +1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j + 1]

Additional information

Used simplifier rules: ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i; Used terms: j + 1