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Proof step 5 from proof int2bits-succ (previous step)

0 ≤ j ⊦ uint2bits(j + 1) = sgn(false ' + int2bits(j) +1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ j → uint2bits(j + 1) = sgn(false ' + uint2bits(j) +1)
Proof step 7:
0 ≤ j, 0 ≤ j ⊦ sgn(false ' + uint2bits(j) +1) = sgn(false ' + int2bits(j) +1)

Rule argument

name: uint2bits-succ rotate: F subst: [j] → [j]

Additional information

Used terms: j