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Proof step 2 from proof int2bits-true (previous step)

int2bits(j) = true ' ⊦ j = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 4:
¬ 0 ≤ j, int2bits(j) = true ' ⊦ j = ~1

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used simplifier rules: uint2bits-not-one: 0 ≤ i ⊦ uint2bits(i) ≠ true ';% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j; Used terms: j