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Proof step 16 from proof int2bits-truein-01 (previous step)

int2bits(j) = true ' + bits, 2 ^ n→i(# bits) + j = 0, j < 2 ^ n→i(# bits), 0 < 2 ^ n→i(# bits), j < 0, j + 1 < 2 ^ n→i(# bits) ⊦ j = 0, true ∈ bits, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: n→i(# bits)

Additional information

Used simplifier rules: ⊦ ¬ n→i(n) < 0; Used terms: n→i(# bits)