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Proof step 5 from proof int2bits-truein-01 (previous step)

⊦ j = 0, true ∈ int2bits(j).rest, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ 0 ≤ i → int2bits(i) = uint2bits(i)
Proof step 7:
¬ 0 ≤ j ⊦ j = 0, true ∈ int2bits(j).rest, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0
Proof step 18:
0 ≤ j ⊦ j = 0, true ∈ uint2bits(j).rest, ∃ i. ¬ i < 0 ∧ 2 ^ i + j = 0

Rule argument

name: int2bits-pos rotate: F subst: [i] → [j]

Additional information

Used terms: j