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Proof step 7 from proof int2bits-truein (previous step)

j < 0, j < 0 ⊦ j = 0, true ∈ sgn(bitsinvert(uint2bits(abs(j))) +1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j < 0 ⊦ j = 0, true ∈ sgn(bitsinvert(uint2bits(~ j)) +1)

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;