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Proof step 5 from proof int2bits-truetrue-01 (previous step)

int2bits(j) = true ' + true ' + bits, j < 0 ⊦ j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i < 0 → int2bits(i) = sgn(bitsinvert(uint2bits(abs(i))) +1)

Rule argument

name: int2bits-neg rotate: F subst: [i] → [j]

Additional information

Used simplifier rules: ⊦ i < 0 → abs(i) = ~ i;% ⊦ sgn(bits) ≠ boolvar ' + boolvar ' + bits0;% ⊦ (bits + bits0) + bits1 = bits + bits0 + bits1; Used terms: j